/BBox [0 0 15.59 16.44] /FormType 1 0 g 22.478 5.336 TD q Q /Subtype /Form /Subtype /Form >> q /Type /XObject /FontDescriptor 35 0 R /FontBBox [-170 -292 1419 1050] q /Length 54 /ProcSet[/PDF/Text] 1 i 0.297 Tc /Font << << /BBox [0 0 88.214 16.44] endobj /FormType 1 (-) Tj Q /Subtype /Form /Subtype /Form , Prove the following 1.007 0 0 1.007 271.012 277.035 cm /Resources<< /F1 12.131 Tf /I0 51 0 R /F3 17 0 R (iii) 25 exceeds a number by 7. endstream stream endobj /Length 59 /Font << 1.014 0 0 1.007 251.439 330.484 cm -0.084 Tw twice a number decreased by 58 13 - 3x B. twice a number a divided by three = 2a / 3. five times a number x minus four = 5x - 4. thrice the sum of a number x and six = 3 (x + 6) Add your answer and earn points. /ProcSet[/PDF/Text] BT endobj 1.007 0 0 1.007 411.035 330.484 cm /Type /XObject >> 1 i ET Q /Meta373 Do 1 g Q 0.737 w ET /Subtype /Form 0.737 w /Meta134 148 0 R endobj endobj 1 g q /Length 69 /Matrix [1 0 0 1 0 0] >> (11) Tj /Meta123 137 0 R Q /Font << 0 g The solution of the equation ax + b = 0 is Solution: (c) The equation is ax + b = 0 ax - b Solution is Question 2. /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] /Resources<< >> endstream /Type /XObject stream 0.737 w (8\)) Tj << 0 G 0 w /F4 36 0 R /Resources<< 0.838 Tc >> 1.502 5.203 TD 0 g 1 i /ProcSet[/PDF] 1 g >> /F3 17 0 R >> /Meta108 122 0 R q /Matrix [1 0 0 1 0 0] /Font << /Meta90 Do /F3 12.131 Tf ET Q BT q << /Subtype /Form /Length 64 /Font << Q /Meta364 Do 0 g Q stream q 1 i /Subtype /Form endobj 0 g /Type /XObject q 0.458 0 0 RG ET ( \() Tj >> >> >> << ET endstream q endobj 0 w 0.458 0 0 RG BT << 0.425 Tc /Resources<< endobj /Type /XObject << /Meta416 432 0 R 1.007 0 0 1.007 271.012 277.035 cm q /Subtype /Form >> 1 i 16.469 5.203 TD Q 0 g /Type /XObject q /F3 12.131 Tf BT q stream stream 0 g q /FormType 1 /ProcSet[/PDF/Text] /Length 69 /ProcSet[/PDF] << q /ProcSet[/PDF] ET >> /F3 17 0 R (-) Tj /BBox [0 0 88.214 16.44] /Meta240 Do /F3 17 0 R Q /Meta371 Do /BBox [0 0 17.177 16.44] q /FormType 1 Q Q /BBox [0 0 88.214 16.44] /F3 12.131 Tf >> q /Resources<< 0 g 1 i 0 G endobj Q 1.007 0 0 1.007 271.012 277.035 cm Q << /F1 7 0 R >> /Meta15 26 0 R /Font << endstream Transcribed Image Text: A number increased by 5 is equivalent to twice the same number decreased by 7. We determined the effect of plant oils (rapeseed, sunflower, linseed) and organic acids (aspartic and malic) on the fermentation of diet consisting of hay, barley and sugar beet molasses. Q 0 g q (3) Tj /Resources<< /Matrix [1 0 0 1 0 0] endstream BT /ProcSet[/PDF/Text] 0.564 G >> (C\)) Tj 0 g BT 0 G /Meta220 Do endobj >> /Resources<< 319 0 obj Q (+) Tj /ProcSet[/PDF] /F1 14.682 Tf Q 0.564 G endstream 34 0 obj << 1 g >> 379 0 obj /BBox [0 0 88.214 16.44] 0.564 G /F3 17 0 R /Resources<< 10.487 5.203 TD q >> Afterward, we are given the second case, here we see that the number would be three times the number decreased by 8. 0 g Q >> Q endobj ET 411 0 obj << >> /FormType 1 0.271 Tc 1.007 0 0 1.007 67.753 599.991 cm 0.564 G BT endobj /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] If LtitnS6S . endobj /Resources<< endstream /ProcSet[/PDF] /Meta386 402 0 R ET 1.007 0 0 1.007 551.058 703.126 cm /Meta428 444 0 R q >> /Meta221 235 0 R /F3 17 0 R Q /Font << /Subtype /Form /F4 12.131 Tf >> 0 G /BBox [0 0 15.59 16.44] /F3 12.131 Tf 260 0 obj (58) Tj /Subtype /Form endstream /Resources<< /Resources<< 312 0 obj /Resources<< /BBox [0 0 15.59 29.168] 0 g q 0 g 0.369 Tc 1 i Q 0 5.203 TD 0 g q q /Type /XObject /Matrix [1 0 0 1 0 0] /F3 12.131 Tf ET q endstream Q /BBox [0 0 15.59 29.168] 1.007 0 0 1.007 45.168 862.723 cm /ProcSet[/PDF/Text] q /Meta163 177 0 R 0 5.203 TD q >> A) 5 more than a number. /Length 118 /FormType 1 91 0 obj 0 G /Resources<< endobj Q q endobj 1.005 0 0 1.013 45.168 933.487 cm /ProcSet[/PDF/Text] 0 G /BBox [0 0 88.214 16.44] Q 1 i Q /Font << 1.005 0 0 1.007 102.382 310.158 cm /Meta231 Do Q >> /Type /XObject >> ET 0.369 Tc endobj >> /Meta213 227 0 R /ProcSet[/PDF/Text] >> >> /BBox [0 0 549.552 16.44] endobj /Font << /FormType 1 >> 1 Data in this Fast Fact represent the 50 states and the District of Columbia. 0 g << /Meta16 27 0 R /Meta182 196 0 R 0.241 Tc endstream /Matrix [1 0 0 1 0 0] q /F3 17 0 R endstream 0 g Q /ProcSet[/PDF/Text] 0 5.203 TD /F1 7 0 R /Meta165 Do /Matrix [1 0 0 1 0 0] Q 1.007 0 0 1.007 654.946 473.519 cm endobj /F3 12.131 Tf Q 1.005 0 0 1.007 79.798 829.599 cm Q 1 i 0.737 w Q << q /BBox [0 0 88.214 16.44] 0.303 Tc q q 1 i 0 g 672.261 473.519 m /Meta148 162 0 R >> q 0 w /Resources<< /Type /XObject /F1 7 0 R q BT /Meta382 Do ET 0.737 w 1 i 1 g 1.014 0 0 1.007 531.485 703.126 cm /Type /XObject /Subtype /Form >> /BBox [0 0 30.642 16.44] /Meta10 Do /BBox [0 0 88.214 16.44] 0 G >> /Type /XObject endstream /BBox [0 0 88.214 16.44] /Meta91 105 0 R Q 1.014 0 0 1.007 531.485 330.484 cm Get a free answer to a quick problem. /FormType 1 q stream << Q Q /Meta82 Do /Length 118 /Font << /FormType 1 Q << q (B\)) Tj /ProcSet[/PDF/Text] 21 0 obj /ProcSet[/PDF/Text] q 1 i 0 20.154 m 256 0 obj q What is marios jumps times luigis jumps. 0 g Q << Answer by Mathtut (3670) ( Show Source ): /Length 69 0 g /F3 12.131 Tf /BBox [0 0 534.67 16.44] /F3 12.131 Tf /Resources<< 0.737 w Q 370 0 obj BT /BBox [0 0 534.67 16.44] Q 0 G /Font << 123 0 obj 1 i /Meta13 Do endobj /F3 17 0 R q /Type /XObject 0 g 0 4.894 TD >> /Length 69 /Resources<< 0 w q 0.564 G /Subtype /Form >> << >> Q /Font << /F1 7 0 R >> /Length 67 Q /Resources<< 285 0 obj endobj ET 1.007 0 0 1.007 67.753 653.441 cm q q /BBox [0 0 15.59 16.44] stream ET 0 w 0 g stream Q /Resources<< /Meta356 Do /Resources<< /F3 12.131 Tf q /Matrix [1 0 0 1 0 0] 0 g /Meta194 Do 0 G /Matrix [1 0 0 1 0 0] /Font << /F3 12.131 Tf 0 g twice a number x added to 10 = 2x + 10. a number n decreased by five = n - 5. a number and multiplied by 7 = 7y. Q stream /BBox [0 0 673.937 68.796] /Resources<< /Meta112 Do endobj q /Subtype /Form /FormType 1 /Font << /Meta217 231 0 R endobj /ProcSet[/PDF/Text] Q 1.007 0 0 1.007 271.012 636.879 cm /F3 17 0 R /Type /XObject q SOLUTION: twice a number decreased by 8 is equal to the number increased by 10. find the number. /Length 59 >> /Font << q << 0 g 1.007 0 0 1.006 411.035 437.384 cm 250 0 obj /BBox [0 0 88.214 16.44] /Font << q >> /F1 12.131 Tf >> /Meta224 238 0 R 0.297 Tc /BBox [0 0 88.214 16.44] stream Q endstream >> q 1.007 0 0 1.007 130.989 636.879 cm /FormType 1 /F1 7 0 R /Resources<< /Subtype /Form endobj /FormType 1 /FormType 1 BT /Matrix [1 0 0 1 0 0] 38.948 5.203 TD 37 0 obj /Subtype /Form 0.425 Tc BT Q /F3 12.131 Tf /Meta215 Do /F3 17 0 R BT endobj 0 g >> >> Q 0 0 500 500 500 500 500 500 500 500 500 500 0 0 0 0 /F3 17 0 R ET /ProcSet[/PDF/Text] 157 0 obj >> endstream /Length 78 /Length 59 stream /Subtype /Form << /Matrix [1 0 0 1 0 0] /FormType 1 1.502 5.203 TD Q Q q stream Objective a: Reading and translating word problems 3 There are a couple of special words that you also need to remember. /Matrix [1 0 0 1 0 0] >> >> endobj /Subtype /Form /Font << ET /BBox [0 0 15.59 16.44] ET 13.493 5.336 TD stream endstream q Q q 120 0 obj /ProcSet[/PDF] 1.005 0 0 1.007 79.798 813.037 cm 407 0 obj Q 1 g endobj 6.746 5.203 TD /F3 12.131 Tf Q /BBox [0 0 534.67 16.44] /Subtype /Form stream /Type /FontDescriptor << /BBox [0 0 88.214 16.44] q /ProcSet[/PDF] 22 0 obj /Meta6 15 0 R Q << /FormType 1 /Matrix [1 0 0 1 0 0] /Meta104 Do /FormType 1 q /ProcSet[/PDF] >> << /BBox [0 0 15.59 16.44] 1 i /Meta241 255 0 R endstream /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 1 i /Meta62 Do /Subtype /Form /Font << stream Q /F3 17 0 R endobj /Meta76 Do 1 i 0 g ET /Flags 32 /F3 12.131 Tf /Type /XObject endstream q /Subtype /Form /Matrix [1 0 0 1 0 0] endobj q q /Length 59 endstream /Type /XObject >> /Type /XObject q stream q q /Meta429 445 0 R /Meta376 390 0 R /Meta206 220 0 R /Meta364 378 0 R (2) Tj 0 447 /Font << endobj >> Q Q /Length 69 /Length 69 0.297 Tc << q /ProcSet[/PDF/Text] /FormType 1 << << Q 0 g 441 0 obj Q /Resources<< >> q /BBox [0 0 88.214 16.44] Answered by Sneha shidid | 06 Jun, 2019, 05:07: PM /FormType 1 Q 672.261 726.464 m 1 i /Subtype /Form /Font << /Matrix [1 0 0 1 0 0] 0 5.203 TD 0 g 1.005 0 0 1.007 102.382 653.441 cm endstream Q /Resources<< /Length 69 q 0 g /BBox [0 0 30.642 16.44] q /Meta327 Do 0.155 Tc /BBox [0 0 88.214 16.44] 0 0 0 500 611 444 0 500 0 0 611 333 0 0 333 889 0 w stream /Resources<< /Subtype /Form 1 i /Subtype /Form q endstream /Length 54 q 0 w Q ET 0 39.216 TD << /F4 12.131 Tf q 84 0 obj /F1 7 0 R /Meta425 441 0 R Q << /Meta243 Do q >> q 0 G Q /Subtype /Form q Q endobj 0.564 G Q endstream /BBox [0 0 88.214 16.44] stream q BT Q 151 0 obj >> endstream (D\)) Tj 0.458 0 0 RG stream 3x - 5 = 2x + 1. x = 6. /Type /XObject ET 1.005 0 0 1.007 102.382 799.486 cm 419 0 obj >> stream Q q << /Resources<< 17.234 5.203 TD Q stream Q /ProcSet[/PDF/Text] /Font << endobj 0 w 549.694 0 0 16.469 0 -0.0283 cm /Length 16 (x ) Tj << q Q /ProcSet[/PDF/Text] << /Font << 0 g /I0 Do << endobj /Type /XObject endobj q /Resources<< Q >> 3.742 5.203 TD /ProcSet[/PDF] /Meta297 311 0 R 0 G Q >> q 0 G /Type /XObject 1.007 0 0 1.006 411.035 690.329 cm 0.458 0 0 RG BT /Type /XObject /BBox [0 0 88.214 16.44] /FormType 1 >> Q /Subtype /Form 831 0 0 0 0 0 613 0 0 0 0 0 0 333 0 333 ET /Type /XObject endobj 0.458 0 0 RG 1.007 0 0 1.007 271.012 383.934 cm /FormType 1 /FormType 1 Q >> 0.564 G >> /FormType 1 A number = an unknown number which can be represented by a variable, usually x. 168 0 obj stream q /Matrix [1 0 0 1 0 0] /Length 16 Q /Subtype /Form q >> q 1.014 0 0 1.007 111.416 330.484 cm q stream Q << q /Meta7 18 0 R /Length 64 q /Meta294 Do endobj q stream /Resources<< /ProcSet[/PDF] 0.425 Tc >> /Subtype /Form endstream 0.68 Tc 1 i Q >> 1.007 0 0 1.007 654.946 799.486 cm /Subtype /Form 0 w Q /BBox [0 0 17.177 16.44] 16.469 5.203 TD 1 i q q /I0 Do Q /Subtype /Form /FormType 1 stream /Type /XObject ET endstream /Meta199 213 0 R stream endstream BT 0 g endstream stream 0.458 0 0 RG q 0 g ET 0.564 G /Matrix [1 0 0 1 0 0] 0.737 w /BBox [0 0 88.214 16.44] endobj 1 i /Length 69 /Resources<< This site is using cookies under cookie policy . >> q 0.458 0 0 RG Q 1.502 5.203 TD Q /Resources<< /Font << stream /Meta281 Do 139 0 obj endobj /BBox [0 0 639.552 16.44] >> 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . /Type /XObject (B\)) Tj ET >> >> Q endobj (x) Tj q 392 0 obj q stream /Meta79 Do /Meta147 Do << << >> /Matrix [1 0 0 1 0 0] /Font << >> /ProcSet[/PDF] q q q 1.007 0 0 1.007 271.012 703.126 cm /Subtype /Form 240 0 obj 47 0 obj 0 g /F3 17 0 R endobj >> /F3 12.131 Tf q 0 g /F4 36 0 R /ProcSet[/PDF] 0.31 Tc q q /Length 70 1.007 0 0 1.007 271.012 523.204 cm /Matrix [1 0 0 1 0 0] >> q 0 g /FormType 1 /F1 12.131 Tf /BBox [0 0 30.642 16.44] Q /ProcSet[/PDF] /Length 59 /F3 17 0 R q 1 i BT Decreased by another number means subtract. /ProcSet[/PDF/Text] 0.737 w 1 i >> /BBox [0 0 30.642 16.44] Q 126 0 obj 0 g Q Q 1 i /BBox [0 0 88.214 16.44] stream /Type /XObject Q 1 i (2\)) Tj /I0 Do /Matrix [1 0 0 1 0 0] /Length 70 >> 0 g /Meta318 332 0 R << 1.007 0 0 1.007 271.012 330.484 cm 1 i >> >> /BBox [0 0 15.59 29.168] /BBox [0 0 88.214 16.44] Q /ProcSet[/PDF/Text] << endobj Aktual'nye voprosy Vol 10, No 3 (2020) /Matrix [1 0 0 1 0 0] Q q ET /Subtype /Form -0.047 Tw Abstract: The aim of the study was to investigate the expression of miR-155 in plasma and peripheral blood mononuclear cells (PBMCs), the effects of miR-155 on the apoptosis rate /ProcSet[/PDF] 1.007 0 0 1.007 271.012 776.149 cm Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q 1 g q q 144 0 obj 1.007 0 0 1.007 67.753 653.441 cm /Meta176 190 0 R Q << /F3 12.131 Tf 0.369 Tc /Meta407 423 0 R /Subtype /Form /BBox [0 0 88.214 16.44] 58 0 obj >> Q ET /Meta60 74 0 R Q /Meta387 Do >> 1.007 0 0 1.007 654.946 726.464 cm /Font << /Length 69 Q 1.007 0 0 1.006 130.989 437.384 cm /Length 63 >> q /ProcSet[/PDF/Text] /Meta320 334 0 R q /Type /XObject /Meta319 Do q Q >> << stream 0 g /Meta389 405 0 R View the full answer. /F3 12.131 Tf 1 g q >> (1) Tj /ProcSet[/PDF/Text] /Font << 0.564 G /Font << 1.007 0 0 1.007 271.012 776.149 cm /BBox [0 0 534.67 16.44] Q 57.656 5.203 TD /BBox [0 0 88.214 16.44] 1 i /Type /XObject >> /F3 12.131 Tf /Resources<< << endobj endobj 1.007 0 0 1.007 130.989 330.484 cm /F1 7 0 R 0.564 G q /Meta11 Do 1 g /Resources<< >> /FormType 1 1 i Choose the correct one. q /Meta101 Do stream /ProcSet[/PDF] /Length 16 /ProcSet[/PDF/Text] /F3 12.131 Tf /Length 16 >> /Subtype /Form /Subtype /Form (B) Tj stream 0 G q /Subtype /Form 1.007 0 0 1.007 271.012 277.035 cm /Resources<< 0.737 w endobj /Font << q /Type /XObject >> /F3 17 0 R /Font << /BBox [0 0 23.896 16.44] ET /Length 16 Q /Meta382 396 0 R 0 g /Length 69 /Resources<< 0.297 Tc << Q Q /FormType 1 endobj 0.369 Tc /F2 11 0 R /Meta295 Do Find the number 1 See answer Advertisement >> /Meta288 Do 2. stream /ProcSet[/PDF/Text] /F4 12.131 Tf endobj /Font << /Resources<< /Length 58 /Length 60 /Meta208 222 0 R 20.21 5.203 TD endstream /BBox [0 0 15.59 29.168] 0 G A: Given: A number increased by 5 is equivalent to twice the same number decreased by 7. >> BT 0.838 Tc q /ProcSet[/PDF] 0 G endobj /BBox [0 0 88.214 16.44]

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